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Create maximum-number-of-non-overlapping-palindrome-substrings.cpp
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// Time: O(n * k)
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// Space: O(1)
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// greedy
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class Solution {
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public:
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int maxPalindromes(string s, int k) {
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int result = 0;
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for (int mid = 0, prev = 0; mid < 2 * size(s) - 1; ++mid) {
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int left = mid / 2, right = mid / 2 + mid % 2;
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while (left >= prev && right < size(s) && s[left] == s[right]) {
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if (right - left + 1 >= k) {
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prev = right + 1;
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++result;
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break;
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}
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--left, ++right;
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}
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}
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return result;
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}
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};

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