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Create minimum-number-of-operations-to-make-string-sorted.cpp
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// Time: O(26 * n) = O(n)
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// Space: O(26) = O(1)
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class Solution {
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public:
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int makeStringSorted(string s) { // count of prev_permutation
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static const int MOD = 1e9 + 7;
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array<int, 26> count = {0};
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int result = 0, total = 0, comb_total = 1;
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for (int i = size(s) - 1; i >= 0; --i) {
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int num = s[i] - 'a';
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comb_total = ((comb_total * int64_t(size(s) - i) % MOD) * inverse(++count[num], MOD)) % MOD;
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result = (result + ((comb_total * accumulate(cbegin(count), cbegin(count) + num, 0LL) % MOD) * inverse(size(s) - i, MOD) % MOD)) % MOD;
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}
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return result;
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}
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private:
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int inverse(int n, int m) {
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static vector<int> inv = {0, 1};
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for (int i = size(inv); i <= n; ++i) { // lazy initialization
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inv.emplace_back(inv[m % i] * int64_t(m - m / i) % m); // https://cp-algorithms.com/algebra/module-inverse.html
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}
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return inv[n];
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}
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};

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