[Please read the message below]Why can't we keep monitoring the response?

[bbhxwl]

Please do not submit this issue.

• I understand

[bbhxwl]

from playwright.sync_api import sync_playwright
import time


def main():
    with sync_playwright() as p:
        browser = p.chromium.launch(headless=False)
        page = browser.new_page()
        def response(response):
            print("url", response.request.method, response.url)

        page.on("response", response)
        page.goto("https://google.com")
        try:
            while True:
                time.sleep(1)
        except KeyboardInterrupt:
            print("q")


if __name__ == "__main__":
    main()

[bbhxwl]

Refresh the page, he will no longer listen for any requests.

[mxschmitt]

Probably related to this: https://playwright.dev/python/docs/library#timesleep-leads-to-outdated-state

Try to use page.wait_for_timeout(1000) instead.

[bbhxwl]

Probably related to this: https://playwright.dev/python/docs/library#timesleep-leads-to-outdated-state

Try to use page.wait_for_timeout(1000) instead.

Thank you, I tested it and it can solve my problem. I just need to wait for a long time, right?

[mxschmitt]

Yes.

[bbhxwl]

Yes.

But in the future, he won't continue to execute the code behind me, right? If I wait for a short time and he executes my final code, the program will automatically shut down. How should this be resolved?