Re: [wxlua-users] Simple wxLua web access?

lostgallifreyan wrote:
> Thankyou, that looks comprehensible to me, though I got errors. 
> (First had to remove the semicolon, then saw 'stream' reported as nil
>  on line 3).

Strange, in the message i sent, there was no semicolon.

> I don't know how much context this needs, but it does look like it 
> needs something else to make it work.

It does not need anything else. Just save it to a file and execute it
with wxlua on the command line. At least on Linux (wxLua 2.8.10.0) it
will print the source of the webpage.

Here is an example using a GUI for output:

local frame = wx.wxFrame(wx.NULL, wx.wxID_ANY, "wxURL Demo",
                         wx.wxDefaultPosition, wx.wxSize(450, 450),
                         wx.wxDEFAULT_FRAME_STYLE)

local textCtrl = wx.wxTextCtrl(frame, wx.wxID_ANY, "",
                               wx.wxDefaultPosition,
                               wx.wxDefaultSize,
                               wx.wxTE_MULTILINE)

local url = wx.wxURL("http://www.google.com")
local stream = url:GetInputStream()
while stream:CanRead() do
  textCtrl:AppendText(stream:Read(78))
end

frame:Show(true)