feature: zigzag-conversion

Author: MyHerux

code/source/convert.java

@@ -0,0 +1,31 @@
+public class convert {
+
+
+    public static String convert(String s, int numRows) {
+        int length = s.length();
+        int nodeLength = numRows * 2 - 2;
+
+        if (length == 0 | numRows == 0 | numRows == 1) {
+            return s;
+        }
+        String result = "";
+        for (int i = 0; i < numRows; i++) {
+            for (int j = i; j < length; j += nodeLength) {
+                // 整列数据直接等差
+                result += s.charAt(j);
+                int single = j - 2 * i + nodeLength;
+                // 去除首行，尾行，且不能超过最长长度
+                if (i != 0 && i != numRows - 1 && single < length) {
+                    result += s.charAt(single);
+                }
+            }
+        }
+
+        return result;
+    }
+
+    public static void main(String[] args) {
+        System.out.println(convert("ABCDEFGHIGKLMNO", 5));
+    }
+
+}

solution/leetcode/6.Z字型变化.md

@@ -0,0 +1,71 @@
+# Z字型变化
+
+## 日期
+
+2018-11-15
+
+## 题目描述
+
+将字符串 "PAYPALISHIRING" 以Z字形排列成给定的行数：
+
+```
+P   A   H   N
+A P L S I I G
+Y   I   R
+```
+
+之后从左往右，逐行读取字符："PAHNAPLSIIGYIR"
+
+实现一个将字符串进行指定行数变换的函数:
+
+string convert(string s, int numRows);
+
+示例：
+
+```
+示例 1:
+
+输入: s = "PAYPALISHIRING", numRows = 3
+输出: "PAHNAPLSIIGYIR"
+示例 2:
+
+输入: s = "PAYPALISHIRING", numRows = 4
+输出: "PINALSIGYAHRPI"
+解释:
+
+P     I    N
+A   L S  I G
+Y A   H R
+P     I
+```
+
+## 想法
+
+## My
+
+```
+class Solution {
+    public String convert(String s, int numRows) {
+               int length = s.length();
+        int nodeLength = numRows * 2 - 2;
+
+        if (length == 0 | numRows == 0 | numRows == 1) {
+            return s;
+        }
+        String result = "";
+        for (int i = 0; i < numRows; i++) {
+            for (int j = i; j < length; j += nodeLength) {
+                // 整列数据直接等差
+                result += s.charAt(j);
+                int single = j - 2 * i + nodeLength;
+                // 去除首行，尾行，且不能超过最长长度
+                if (i != 0 && i != numRows - 1 && single < length) {
+                    result += s.charAt(single);
+                }
+            }
+        }
+
+        return result;
+    }
+}
+```