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| 1 | +package BinaryTree; |
| 2 | + |
| 3 | +import javax.management.RuntimeMBeanException; |
| 4 | + |
| 5 | +/** |
| 6 | + * Created by dheeraj on 7/9/2016. |
| 7 | + */ |
| 8 | +public class TreeFromInOrderLevelOrder { |
| 9 | + static int in[] = new int[]{4, 8, 10, 12, 14, 20, 22}; |
| 10 | + static int level[] = new int[]{20, 8, 22, 4, 12, 10, 14}; |
| 11 | + |
| 12 | + static Node makeTree(int start, int end, int rootDataIndex) { |
| 13 | + if (start > end) { |
| 14 | + return null; |
| 15 | + } |
| 16 | + if (start == end) { |
| 17 | + return new Node(level[rootDataIndex]); |
| 18 | + } |
| 19 | + Node root = new Node(level[rootDataIndex]); |
| 20 | + int mid = -1; |
| 21 | + for (int x = start; x <= end; x++) { |
| 22 | + if (level[rootDataIndex] == in[x]) { |
| 23 | + mid = x; |
| 24 | + break; |
| 25 | + } |
| 26 | + } |
| 27 | + |
| 28 | + int left = -1; |
| 29 | + //search first elment in level order which is |
| 30 | + // present in pre order,that level order lement is root |
| 31 | + for (int y = 0; y <= level.length - 1; y++) { |
| 32 | + for (int x = start; x <= mid - 1; x++) { |
| 33 | + if (level[y] == in[x]) { |
| 34 | + left = y; |
| 35 | + break; |
| 36 | + } |
| 37 | + } |
| 38 | + if (left != -1) { |
| 39 | + break; |
| 40 | + } |
| 41 | + } |
| 42 | + int right = -1; |
| 43 | + for (int y = 0; y <= level.length - 1; y++) { |
| 44 | + for (int x = mid + 1; x <= end; x++) { |
| 45 | + if (level[y] == in[x]) { |
| 46 | + right = y; |
| 47 | + break; |
| 48 | + } |
| 49 | + } |
| 50 | + if (right != -1) { |
| 51 | + break; |
| 52 | + } |
| 53 | + } |
| 54 | + if ((left != -1)) { |
| 55 | + root.left = makeTree(start, mid - 1, left); |
| 56 | + } |
| 57 | + if (right != -1) { |
| 58 | + root.right = makeTree(mid + 1, end, right); |
| 59 | + } |
| 60 | + return root; |
| 61 | + } |
| 62 | + |
| 63 | + |
| 64 | + public static void main(String[] strings) { |
| 65 | + Node node = makeTree(0, in.length - 1, 0); |
| 66 | + System.out.println(); |
| 67 | + } |
| 68 | +} |
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