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1 parent 99fd83e commit a8e8b81Copy full SHA for a8e8b81
SQL Deep Dive/Having/questions.sql
@@ -21,15 +21,18 @@ SELECT e.emp_no, COUNT(s.salary) AS "Salary changes"
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FROM employees as e
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INNER JOIN salaries as s USING(emp_no)
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INNER JOIN dept_emp AS d USING(emp_no)
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-INNER JOIN departments as de ON de.dept_no = d.dept_no
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-WHERE de.dept_name = 'Development'
+WHERE d.dept_no = 'd005'
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GROUP BY e.emp_no
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-HAVING COUNT(s.salary) > 15
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-
+HAVING COUNT(s.salary) > 15;
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/*
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* Show me all the employees that have worked for multiple departments
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* Database: Employees
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*/
+SELECT e.emp_no, COUNT(d.dept_no) AS "No_dept"
+FROM employees as e
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+JOIN dept_emp AS d USING(emp_no)
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+GROUP BY e.emp_no
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+HAVING COUNT(d.dept_no) > 1;
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