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Merge pull request jimmysong#110 from chanhosuh/inscribing_the_target
Ch 3: inscribing the target, better wording
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ch03.asciidoc

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@@ -702,8 +702,8 @@ If we know _e_, we have:
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This means that any (_u_,_v_) combination that satisfies the preceding equation will suffice.
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If we don't know _e_, we'll have to play with (_u_,_v_) until __e = (k–u)/v__.
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If we could solve this with any (_u_,_v_) combination, that would mean we'd have solved _P_ = _eG_ while knowing only _P_ and _G_.
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Now suppose we don't know _e_, but we can solve __uG + vP = kG__ with some (_u_,_v_) combination.
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Then __e = (k–u)/v__ gives a solution to _P_ = _eG_ while knowing only _P_ and _G_.
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In other words, we'd have broken the discrete log problem.
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This means to provide a correct _u_ and _v_, we either have to break the discrete log problem or know the secret _e_.

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