Skip to content

Properly parse @$x += $y as @($x += $y) #282

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged

Conversation

TysonAndre
Copy link
Contributor

Fixes one edge case in #19

Also, fix parsing of @$x instanceof $y.
My earlier PR fixed !$x instanceof $y but broke that.

Copy link
Member

@roblourens roblourens left a comment

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

Thanks for the PR! Looks good to me. I'll let you fix the merge conflict.

Fixes one edge case in microsoft#19

Also, fix parsing of `@$x instanceof $y`.
My earlier PR fixed `!$x instanceof $y` but broke that.
@TysonAndre TysonAndre force-pushed the force-assignment-expression branch from 3f9c698 to 0a96f2e Compare March 9, 2019 19:10
@TysonAndre
Copy link
Contributor Author

ok, fixed

@roblourens roblourens merged commit 89386de into microsoft:master Mar 9, 2019
@TysonAndre TysonAndre deleted the force-assignment-expression branch March 27, 2021 16:50
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Labels
None yet
Projects
None yet
Development

Successfully merging this pull request may close these issues.

2 participants