comparison-with-callable false positive then type of variable is a Callable

[LefterisJP]

Small note: You guys are awesome. Thanks a lot for pylint 🤗

Steps to reproduce

import operator
from typing import Callable


def foo(op: Callable = operator.add) -> None:
    if op == operator.sub:
        print('do something with sub')
    elif op == operator.add:
        print('do something with add')
    else:
        print('no idea')

Current behavior

Getting:

test2.py:6:7: W0143: Comparing against a callable, did you omit the parenthesis? (comparison-with-callable)
test2.py:8:9: W0143: Comparing against a callable, did you omit the parenthesis? (comparison-with-callable)

Expected behavior

I would expect that this error should not be returned since it's obviously an intended comparison with a callable. You want to do something depending on the callable type that op is. So no need for parentheses as suggested by the example here.

pylint --version output

pylint 2.6.0
astroid 2.4.2
Python 3.7.9 (default, Sep 26 2020, 15:11:06)
[GCC 10.2.0]

[PCManticore]

Thanks for the report, I can confirm this is a bug.

[jacobtylerwalls]

Can't reproduce on main (8854350)