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Java's BitSet class implements a vector of bit values (i.e.: () or ()) that grows as needed, allowing us to easily manipulate bits while optimizing space (when compared to other collections). Any element having a bit value of is called a set bit.

Given BitSets, and , of size where all bits in both BitSets are initialized to , perform a series of operations. After each operation, print the number of set bits in the respective BitSets as two space-separated integers on a new line.

Input Format

The first line contains space-separated integers, (the length of both BitSets and ) and (the number of operations to perform), respectively. The subsequent lines each contain an operation in one of the following forms:

AND OR XOR FLIP SET In the list above, is the integer or , where denotes and denotes . is an integer denoting a bit's index in the BitSet corresponding to .

For the binary operations , , and , operands are read from left to right and the BitSet resulting from the operation replaces the contents of the first operand. For example:

AND 2 1 is the left operand, and is the right operand. This operation should assign the result of to .

Constraints

Output Format

After each operation, print the respective number of set bits in BitSet and BitSet as space-separated integers on a new line.

Sample Input

5 4 AND 1 2 SET 1 4 FLIP 2 2 OR 2 1 Sample Output

0 0 1 0 1 1 1 2 Explanation

Initially: , , , and . At each step, we print the respective number of set bits in and as a pair of space-separated integers on a new line.

, The number of set bits in and is .

Set to (). , . The number of set bits in is and is .

Flip from () to (). , . The number of set bits in is and is .

. , . The number of set bits in is and is .

Language Java 8 More 123456789 } } Line: 9 Col: 2

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import java.util.BitSet; import java.util.Scanner;

public class Solution {

public static void main(String[] args) {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */

    Scanner scanner = new Scanner(System.in);

    int N = scanner.nextInt();
    int M = scanner.nextInt();

    BitSet[] B = new BitSet[]{new BitSet(N), new BitSet(N)};

    for( int i=0; i<M; i++ ) {

        String cmd = scanner.next();
        int left = scanner.nextInt()-1;
        int right = scanner.nextInt()-1;

        switch( cmd ) {
            case "AND" -> B[left].and(B[right]); 
            case "OR" -> B[left].or(B[right]);
            case "XOR" -> B[left].xor(B[right]);
            case "SET" -> B[left].set(right+1); 
            case "FLIP" -> B[left].flip(right+1); 
            default -> {}
        }                        

        System.out.print(B[0].cardinality());
        System.out.print(" ");
        System.out.print(B[1].cardinality());
        System.out.println();
    }       
    scanner.close();

}

}

My attempt:

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        
        int bitSetSize = sc.nextInt();
        BitSet b1 = new BitSet(bitSetSize);
        BitSet b2 = new BitSet(bitSetSize);
        BitSet[] bitSets = {b1, b2};
        
        int queryCount = sc.nextInt();
        
        for (int i = 0; i < queryCount; i++) {
            String query = sc.next();
            int arg1 = sc.nextInt();
            int arg2 = sc.nextInt();
            switch (query) {
                case "AND" -> bitSets[arg1 - 1].and(bitSets[arg2 - 1]);
                case "OR" -> bitSets[arg1 - 1].or(bitSets[arg2 - 1]);
                case "XOR" -> bitSets[arg1 - 1].xor(bitSets[arg2 - 1]);
                case "FLIP" -> bitSets[arg1 - 1].flip(arg2);
                case "SET" -> bitSets[arg1 - 1].set(arg2);
            }
            System.out.println(bitSets[0].cardinality() + " " + bitSets[1].cardinality());
        }
        
        sc.close();
    }
}