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  2. Java
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  4. Java Regex
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Java Regex

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  • vitalii_iandulov
     + 0 comments
    public class Solution {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        while (scan.hasNext())
           System.out.println(new MyRegex(scan.nextLine()).isValidIp());
        scan.close();
    }
}

class MyRegex {
    private String val;
    private static final String IP_REG_PATTERN_STRING 
        = "((25[0-5]"
        + "|2[0-4][0-9]"
        + "|[0-1]?[0-9]?[0-9])\\.){3}"
        
        + "(2[0-5][0-5]"
        + "|2[0-4][0-9]"
        + "|[0-1]?[0-9]?[0-9])";
    
    public MyRegex(String val){
        this.val = val;
    }
    
    public boolean isValidIp(){
        return this.val.matches(MyRegex.IP_REG_PATTERN_STRING);
    }
}

  • laarianeamine
     + 0 comments

    class MyRegex{ String pattern ="((2[0-5][0-5]|2[0-4][0-9]|[0-1]?[0-9]?[0-9])\.){3}(2[0-5][0-5]|2[0-4][0-9]|[0-1]?[0-9]?[0-9])"; }

  • nishant_sanjay_1
     + 0 comments

    public String pattern = String.format("^%1s\.%1s$", "((\d{1,2})|((0|1)\d{2})|(2[0-4]\d|25[0-5]))");

  • PatriciaCoover45
     + 0 comments

    Thanks for sharing valuable post! ekbet40 Login

  • bhargavi123ammu
     + 0 comments

    import java.util.regex.Matcher; import java.util.regex.Pattern; import java.util.Scanner;

    class Solution{

    public static void main(String[] args){
    Scanner in = new Scanner(System.in);
    while(in.hasNext()){
        String IP = in.next();
        System.out.println(IP.matches(new MyRegex().pattern));
    }

}

    } class MyRegex{ String reg = "([0-9]|[0-9][0-9]|[0|1][0-9][0-9]|2[0-5][0-5]|2[0-4][0-9])"; String pattern = reg+"."+reg+"."+reg+"."+reg; }